Bernstein approximations and Weierstrass' theorem #
We prove that the Bernstein approximations
∑ k : Fin (n+1), f (k/n : ℝ) * n.choose k * x^k * (1-x)^(n-k)
for a continuous function f : C([0,1], ℝ) converge uniformly to f as n tends to infinity.
Our proof follows [Richard Beals' Analysis, an introduction][beals-analysis], §7D. The original proof, due to Bernstein in 1912, is probabilistic, and relies on Bernoulli's theorem, which gives bounds for how quickly the observed frequencies in a Bernoulli trial approach the underlying probability.
The proof here does not directly rely on Bernoulli's theorem, but can also be given a probabilistic account.
- Consider a weighted coin which with probability
xproduces heads, and with probability1-xproduces tails. - The value of
bernstein n k xis the probability that such a coin gives exactlykheads in a sequence ofntosses. - If such an appearance of
kheads results in a payoff off(k / n), then-th Bernstein approximation forfevaluated atxis the expected payoff. - The main estimate in the proof bounds the probability that
the observed frequency of heads differs from
xby more than someδ, obtaining a bound of(4 * n * δ^2)⁻¹, irrespective ofx. - This ensures that for
nlarge, the Bernstein approximation is (uniformly) close to the payoff functionf.
(You don't need to think in these terms to follow the proof below: it's a giant calc block!)
This result proves Weierstrass' theorem that polynomials are dense in C([0,1], ℝ),
although we defer an abstract statement of this until later.
The Bernstein polynomials, as continuous functions on [0,1].
Equations
- bernstein n ν = (bernsteinPolynomial ℝ n ν).toContinuousMapOn unitInterval
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Extension of the positivity tactic for Bernstein polynomials: they are always non-negative.
Equations
- One or more equations did not get rendered due to their size.
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We now give a slight reformulation of bernsteinPolynomial.variance.
Send k : Fin (n+1) to the equally spaced points k/n in the unit interval.
Equations
- bernstein.z k = ⟨↑↑k / ↑n, ⋯⟩
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The n-th approximation of a continuous function on [0,1] by Bernstein polynomials,
given by ∑ k, f (k/n) * bernstein n k x.
Equations
- bernsteinApproximation n f = ∑ k : Fin (n + 1), f (bernstein.z k) • bernstein n ↑k
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We now set up some of the basic machinery of the proof that the Bernstein approximations converge uniformly.
A key player is the set S f ε h n x,
for some function f : C(I, ℝ), h : 0 < ε, n : ℕ and x : I.
This is the set of points k in Fin (n+1) such that
k/n is within δ of x, where δ is the modulus of uniform continuity for f,
chosen so |f x - f y| < ε/2 when |x - y| < δ.
We show that if k ∉ S, then 1 ≤ δ^-2 * (x - k/n)^2.
The modulus of (uniform) continuity for f, chosen so |f x - f y| < ε/2 when |x - y| < δ.
Equations
- bernsteinApproximation.δ f ε h = f.modulus (ε / 2) ⋯
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The set of points k so k/n is within δ of x.
Equations
- bernsteinApproximation.S f ε h n x = {k : Fin (n + 1) | dist (bernstein.z k) x < bernsteinApproximation.δ f ε h}.toFinset
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If k ∈ S, then f(k/n) is close to f x.
If k ∉ S, then as δ ≤ |x - k/n|, we have the inequality 1 ≤ δ^-2 * (x - k/n)^2.
This particular formulation will be helpful later.
The Bernstein approximations
∑ k : Fin (n+1), f (k/n : ℝ) * n.choose k * x^k * (1-x)^(n-k)
for a continuous function f : C([0,1], ℝ) converge uniformly to f as n tends to infinity.
This is the proof given in [Richard Beals' Analysis, an introduction][beals-analysis], §7D, and reproduced on wikipedia.